2010 Mordovia Cup – Doubles

Michail Elgin and Evgeny Kirillov were the defending champions, but they chose to not compete together.
Elgin partnered up with Ilya Belyaev and Kirillov teamed up with Andrey Kuznetsov. They met in the semifinal and Elgin/Belyaev won 6–3, 4–6, [10–1].
This pair defeated Denys Molchanov and Artem Smirnov in the final 3–6, 7–6(6), [11–9].

Doubles
2010 Mordovia Cup
Champions Ilya Belyaev
Michail Elgin
Runners-up Denys Molchanov
Artem Smirnov
Final score3–6, 7–6(6), [11–9]

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Finals
1 A Kedryuk
D Matsukevich
65 5  
  I Belyaev
M Elgin
7 7     I Belyaev
M Elgin
     
  C Gârd
P-A Luncanu
2 6 [7]   I Cervantes-Huegun
P Santos
w/o    
  I Cervantes-Huegun
P Santos
6 3 [10]   I Belyaev
M Elgin
6 4 [10]
4 M Inoyatov
A Sitak
6 6     E Kirillov
A Kuznetsov
3 6 [1]
WC A Manegin
V Rudnev
3 2   4 M Inoyatov
A Sitak
4 3  
  S Krotiouk
A Lobkov
67 1     E Kirillov
A Kuznetsov
6 6  
  E Kirillov
A Kuznetsov
7 6     I Belyaev
M Elgin
3 7 [11]
WC I Rud
R Tudoreanu
3 3   2 D Molchanov
A Smirnov
6 66 [9]
  E Donskoy
K Kravchuk
6 6     E Donskoy
K Kravchuk
6 6  
  C Niland
I Sergeyev
2 4   3 A Kumantsov
D Savić
4 4  
3 A Kumantsov
D Savić
6 6     E Donskoy
K Kravchuk
4 4  
  M Kukushkin
V Reshetnikov
3 7 [10] 2 D Molchanov
A Smirnov
6 6  
  A Boje-Ordóñez
G Olaso
6 5 [8]   M Kukushkin
V Reshetnikov
3 1  
WC A Bury
K Harbatsiuk
6 3 [6] 2 D Molchanov
A Smirnov
6 6  
2 D Molchanov
A Smirnov
3 6 [10]

References

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