2016 Trophée des Alpilles – Doubles

Ken and Neal Skupski were the defending champions and successfully defended their title, defeating David O'Hare and Joe Salisbury 6–7^(5–7), 6–4, [10–5] in the final.

Doubles
2016 Trophée des Alpilles
Champions	Ken Skupski Neal Skupski
Runners-up	David O'Hare Joe Salisbury
Final score	6–7^(5–7), 6–4, [10–5]

Seeds

1. Purav Raja / Divij Sharan (First round)
2. Ken Skupski / Neal Skupski (Champions)
3. Konstantin Kravchuk / Artem Sitak (First round)
4. Grégoire Barrère / Albano Olivetti (Semifinals)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

	First Round							Quarterfinals							Semifinals							Final
	1	P Raja D Sharan	6	2	[5]
		D O'Hare J Salisbury	3	6	[10]				D O'Hare J Salisbury	6	6
	PR	M Bachinger P Gojowczyk	6^2	6	[11]			PR	M Bachinger P Gojowczyk	3	3
		D Medvedev M Viola	7^7	4	[9]											D O'Hare J Salisbury	6	6
	4	G Barrère A Olivetti	7^10	7^10											4	G Barrère A Olivetti	2	4
	WC	M Janvier R Jouan	6^8	6^8				4	G Barrère A Olivetti	6	7^7
		K Coppejans Y Mertens	6	3	[6]				T Draganja A Menéndez-Maceiras	4	6^3
		T Draganja A Menéndez-Maceiras	2	6	[10]																		D O'Hare J Salisbury	7^7	4	[5]
		M Copil S Stakhovsky	6	6																		2	K Skupski N Skupski	6^5	6	[10]
	WC	Alexandre Buchner Boris Vermet	1	3					M Copil S Stakhovsky
		I Sabanov M Sabanov	2	6	[10]				I Sabanov M Sabanov	w/o
	3	K Kravchuk A Sitak	6	3	[6]											I Sabanov M Sabanov	2	2
	WC	Cyril Respaut Nathan Seateun	2	4											2	K Skupski N Skupski	6	6
		A Pavić A Šetkić	6	6					A Pavić A Šetkić	3	6^1
		R Bemelmans J De Loore	6^2	4				2	K Skupski N Skupski	6	7^7
	2	K Skupski N Skupski	7^7	6

References

• Main Draw