2019 Challenger Banque Nationale de Drummondville – Doubles

Joris De Loore and Frederik Nielsen were the defending champions but chose not to defend their title.[1]

Doubles
2019 Challenger Banque Nationale de Drummondville
Champions	Scott Clayton Adil Shamasdin
Runners-up	Matt Reid John-Patrick Smith
Final score	7–5, 3–6, [10–5]

Scott Clayton and Adil Shamasdin won the title after defeating Matt Reid and John-Patrick Smith 7–5, 3–6, [10–5] in the final.

Seeds

1. Matt Reid / John-Patrick Smith (Final)
2. Evan King / Hunter Reese (First round)
3. Scott Clayton / Adil Shamasdin (Champions)
4. Luis David Martínez / Roberto Quiroz (Semifinals)

Draw

Key

• Q = Qualifier
• WC = Wild Card
• LL = Lucky Loser
• Alt = Alternate
• SE = Special Exempt
• PR = Protected Ranking
• ITF = ITF entry
• JE = Junior Exempt
• w/o = Walkover
• r = Retired
• d = Defaulted

	First Round							Quarterfinals							Semifinals							Final
	1	M Reid J-P Smith	6^3	6	[10]
	ITF	MF Descotte S Mansouri	7^7	4	[6]			1	M Reid J-P Smith	7	4	[10]
	WC	Justin Boulais Joshua Peck	6^7	5				WC	F Dancevic F Mergea	5	6	[4]
	WC	F Dancevic F Mergea	7^9	7											1	M Reid J-P Smith	6	6
	4	LD Martínez R Quiroz	6	6											4	LD Martínez R Quiroz	4	1
		L Broady T-S Kwiatkowski	4	4				4	LD Martínez R Quiroz	6	6
		S Diez N Milojević	3	6^3					A Göransson N Pasha	1	3
		A Göransson N Pasha	6	7^7																		1	M Reid J-P Smith	5	6	[5]
		JC Aragone F Romboli	3	2																		3	S Clayton A Shamasdin	7	3	[10]
	ITF	E Furness M Guinard	6	6				ITF	E Furness M Guinard	4	3
	WC	Taha Baadi Liam Draxl	2	3				3	S Clayton A Shamasdin	6	6
	3	S Clayton A Shamasdin	6	6											3	S Clayton A Shamasdin	3	7^7	[10]
		M Viola J Zopp	5	3												D Novikov A Pavić	6	6^4	[5]
		D Novikov A Pavić	7	6					D Novikov A Pavić	6	3	[10]
		JP Fruttero C Harrison	7^7	2	[10]				JP Fruttero C Harrison	3	6	[4]
	2	E King H Reese	6^4	6	[3]

References

1. "Luis David Martínez fue subcampeón en Canadá". 18 March 2018.

• Main Draw