2019 Maia Challenger – Doubles

Doubles
	2019 Maia Challenger
Champions	Andre Begemann; Daniel Masur
Runners-up	Guillermo García López; David Vega Hernández
Final score	7–6(7–2), 6–4

Andre Begemann and Daniel Masur won the title after defeating Guillermo García López and David Vega Hernández 7–6^(7–2), 6–4 in the final.

This was the first edition of the tournament.[1]

Seeds

First Round					Quarterfinals					Semifinals					Final

1	R Arneodo N Monroe	3	7	[8]
	K Drzewiecki S Walków	6	5	[10]		K Drzewiecki S Walków	6⁵	7	[7]
	T Gabashvili P Kotov	6	3	[10]		T Gabashvili P Kotov	7⁷	5	[10]
WC	Nuno Borges Francisco Cabral	4	6	[4]							T Gabashvili P Kotov	3	4
4	S Clayton P Raja	3	2								G García López D Vega Hernández	6	6
WC	Gonçalo Falcão P Sousa	6	6		WC	G Falcão P Sousa	1	4
Alt	A Çelikbilek Vít Kopřiva	4	2			G García López D Vega Hernández	6	6
	G García López D Vega Hernández	6	6													G García López D Vega Hernández	6²	4
WC	T Cação João Monteiro	7⁷	3	[10]												A Begemann D Masur	7⁷	6
	T Draganja Z Kolář	6⁴	6	[3]	WC	T Cação J Monteiro	6⁶	4
	S Mukund VS Prashanth	0	6	[11]		S Mukund VS Prashanth	7⁸	6
3	L Margaroli A Vavassori	6	4	[9]							S Mukund VS Prashanth	7⁷	3	[9]
	A Begemann D Masur	6	4	[10]							A Begemann D Masur	6³	6	[11]
	Sergio Martos Gornés S Puodziunas	4	6	[7]		A Begemann D Masur	7⁷	4	[10]
	I Nedelko D Yevseyev	1	4		2	T Brkić A Pavić	6⁴	6	[7]
2	T Brkić A Pavić	6	6

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