2019 Murray Trophy – Glasgow – Doubles

Gerard Granollers and Guillermo Olaso were the defending champions[1] but chose not to defend their title.

Glasgow – Doubles
2019 Murray Trophy – Glasgow
Champions Ruben Bemelmans
Daniel Masur
Runners-up Jamie Murray
John-Patrick Smith
Final score4–6, 6–3, [10–8]

Ruben Bemelmans and Daniel Masur won the title after defeating Jamie Murray and John-Patrick Smith 4–6, 6–3, [10–8] in the final.

Seeds

Draw

Key

First Round Quarterfinals Semifinals Final
1 J Murray
J-P Smith
6 6
WC Marshall Tutu
David Wright
4 2 1 J Murray
J-P Smith
6 6
Alt A Çelikbilek
C İlkel
77 78 Alt A Çelikbilek
C İlkel
3 4
H Heliövaara
E Ruusuvuori
65 66 1 J Murray
J-P Smith
6 6
4 K Drzewiecki
S Walków
3 6 [10] M Gengel
R Ramanathan
2 3
WC L Johnson
Mark Whitehouse
6 3 [3] 4 K Drzewiecki
S Walków
4 6 [3]
Marek Gengel
R Ramanathan
7 79 M Gengel
R Ramanathan
6 3 [10]
S Clayton
L Glasspool
5 67 1 J Murray
J-P Smith
6 3 [8]
N Kuhn
J Rodionov
w/o R Bemelmans
D Masur
4 6 [10]
G Blancaneaux
A Rinderknech
N Kuhn
J Rodionov
R Bemelmans
D Masur
77 6 R Bemelmans
D Masur
w/o
3 A Göransson
S Verbeek
62 4 R Bemelmans
D Masur
6 4 [11]
J Ocleppo
R Ortega Olmedo
64 5 2 N Lammons
A Šančić
4 6 [9]
Q Halys
Matteo Martineau
77 7 Q Halys
M Martineau
4 2
R Gonzales
A Siljeström
4 63 2 N Lammons
A Šančić
6 6
2 N Lammons
A Šančić
6 77

References

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