1988 United States Senate election in Ohio
The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.[1] As of 2020, this is the last time in a presidential election year Ohio voted differently for president and for senate.
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 County Results Metzenbaum: 50–60% 60–70% 70–80% Voinovich: 50-60% 60-70% | |||||||||||||||||
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| Elections in Ohio |
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Results
| Party | Candidate | Votes | % | ||
|---|---|---|---|---|---|
| Democratic | Howard Metzenbaum (incumbent) | 2,480,038 | 56.97% | ||
| Republican | George Voinovich | 1,872,716 | 42.31% | ||
| Independent | David Marshall | 151 | 0.00% | ||
| Majority | 607,322 | 8.68% | |||
| Turnout | 4,352,905 | 100.00% | |||
| Democratic hold | |||||
See also
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