1991 Tour of Britain
The 1991 Tour of Britain was the fifth edition of the Kellogg's Tour of Britain cycle race and was held from 6 August to 10 August 1991. The race started in Windsor and finished in Leeds.[1] The race was won by Phil Anderson of the Motorola team.
Race details | |||||||||||||||||||||||||||||
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Dates | 6–10 August 1991 | ||||||||||||||||||||||||||||
Stages | 5 | ||||||||||||||||||||||||||||
Winning time | 24h 59' 57" | ||||||||||||||||||||||||||||
Results | |||||||||||||||||||||||||||||
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Route
Stage | Date | Course | Distance | Type | Winner | |
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1 | 6 August | Windsor to Birmingham | 212.9 km (132.3 mi) | Phil Anderson (AUS) | ||
2 | 7 August | Coventry to Lincoln | 191.3 km (118.9 mi) | Johan Museeuw (BEL) | ||
3 | 8 August | Lincoln to Buxton | 183 km (113.7 mi) | Phil Anderson (AUS) | ||
4a | 9 August | Buxton to Manchester | 108 km (67.1 mi) | Gianluca Bortolami (ITA) | ||
4b | Manchester to Liverpool | 91.2 km (56.7 mi) | Rolf Aldag (GER) | |||
5 | 10 August | Liverpool to Leeds | 208 km (129.2 mi) | Hilly stage | Adri van der Poel (NED) |
General classification
Final general classification[1][2]
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References
- "Tour de Grande-Bretagne 1991". Memoire du cyclisme. Archived from the original on 28 August 2004.
- "Anderson gana en Inglaterra" [Anderson wins in England]. El Mundo Deportivo (in Spanish). 11 August 1991. p. 35. Retrieved 24 December 2017.
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