2018 Mumbai Open – Doubles

Victoria Rodríguez and Bibiane Schoofs were the defending champions, but Rodríguez chose not to participate this year.

Doubles
2018 Mumbai Open
Champion Natela Dzalamidze
Veronika Kudermetova
Runner-up Bibiane Schoofs
Barbora Štefková
Final score6–4, 7–6(7–4)

Natela Dzalamidze and Veronika Kudermetova won the title, defeating Schoofs and Barbora Štefková in the final, 6–4, 7–6(7–4).[1]

Seeds

Draw

Key

First Round Quarterfinals Semfinals Final
1 D Jakupović
I Khromacheva
6 6
S Shapatava
E Webley-Smith
0 2 1 D Jakupović
I Khromacheva
6 6
R Bhosale
H Kuwata
7 3 [11] R Bhosale
H Kuwata
3 3
T Mrdeža
A Raina
5 6 [9] 1 D Jakupović
I Khromacheva
5 3
3 N Dzalamidze
V Kudermetova
6 6 3 N Dzalamidze
V Kudermetova
7 6
WC M Jain
M Yadav
1 1 3 N Dzalamidze
V Kudermetova
6 6
M Doi
T Martincová
6 4 [10] M Doi
T Martincová
1 1
V Grammatikopoulou
Jia Lu
2 6 [4] 3 N Dzalamidze
V Kudermetova
6 77
L Kumkhum
P Thombare
2 6 [7] 4 B Schoofs
B Štefková
4 64
S-y Hsieh
N Kostić
6 2 [10] S-y Hsieh
N Kostić
6 63 [5]
E Gorgodze
D Khazaniuk
4 62 4 B Schoofs
B Štefková
1 77 [10]
4 B Schoofs
B Štefková
6 77 4 B Schoofs
B Štefková
3 77 [10]
K-y Ng
S Zheng
4 63 O Danilović
D Kovinić
6 65 [8]
O Danilović
D Kovinić
6 77 O Danilović
D Kovinić
6 6
K Palkina
Y Sizikova
1 1 2 N Hibino
O Kalashnikova
2 1
2 N Hibino
O Kalashnikova
6 6

References

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