2019 Hungarian Open – Doubles

Dominic Inglot and Franko Škugor were the defending champions,[1] but Škugor chose to compete in Barcelona instead. Inglot played alongside Rohan Bopanna, but lost in the quarterfinals to Andre Begemann and Ernests Gulbis.

Doubles
2019 Hungarian Open
Champions Ken Skupski
Neal Skupski
Runners-up Marcus Daniell
Wesley Koolhof
Final score6–3, 6–4
Draw16 (2 WC )
Seeds4

Ken and Neal Skupski won the title, defeating Marcus Daniell and Wesley Koolhof in the final, 6–3, 6–4.

Seeds

Draw

Key

Draw

First Round Quarterfinals Semifinals Final
1 R Bopanna
D Inglot
6 7
Alt T Fabbiano
J Millman
3 5 1 R Bopanna
D Inglot
3 4
Alt A Begemann
E Gulbis
6 7 Alt A Begemann
E Gulbis
6 6
R Jebavý
A Molteni
4 5 Alt A Begemann
E Gulbis
2 77 [6]
3 K Skupski
N Skupski
6 77 3 K Skupski
N Skupski
6 62 [10]
WC M Valkusz
N Zimonjić
0 64 3 K Skupski
N Skupski
78 5 [10]
R Lindstedt
A-u-H Qureshi
3 6 [9] M Demoliner
D Sharan
66 7 [7]
M Demoliner
D Sharan
6 4 [11] 3 K Skupski
N Skupski
6 6
M Daniell
W Koolhof
6 6 M Daniell
W Koolhof
3 4
H Hurkacz
F Martin
2 3 M Daniell
W Koolhof
6 77
WC G Borsos
P Nagy
6 3 [8] 4 R Haase
F Nielsen
4 65
4 R Haase
F Nielsen
2 6 [10] M Daniell
W Koolhof
3 6 [10]
R Albot
N Basilashvili
3 3 K Krawietz
A Mies
6 2 [8]
K Krawietz
A Mies
6 6 K Krawietz
A Mies
3 6 [10]
L Bambridge
J O'Mara
3 6 [10] L Bambridge
J O'Mara
6 4 [6]
2 S González
M Middelkoop
6 3 [8]

References

  1. "Inglot/Skugor Earn Maiden Team Title In Budapest". ATP Tour. 29 April 2018. Retrieved 20 April 2019.
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