Jacksonburg, West Virginia
Jacksonburg is a census-designated place (CDP) in Wetzel County, West Virginia, United States. It lies at an elevation of 748 feet (228 m).[3] As of the 2010 census, its population was 182.[2]
Jacksonburg | |
|---|---|
Census-designated place (CDP) | |
  Jacksonburg Location within the state of West Virginia | |
| Coordinates: 39°31′56″N 80°38′30″W | |
| Country | United States |
| State | West Virginia |
| County | Wetzel |
| Area | |
| • Total | 1.501 sq mi (3.89 km2) |
| • Land | 1.481 sq mi (3.84 km2) |
| • Water | 0.020 sq mi (0.05 km2) |
| Population | |
| • Total | 182 |
| • Density | 120/sq mi (47/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
References
- "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23.
- "U.S. Census website". United States Census Bureau. Retrieved 2011-05-14.
- U.S. Geological Survey Geographic Names Information System: Jacksonburg, West Virginia
Municipalities and communities of Wetzel County, West Virginia, United States | ||
|---|---|---|
| Cities |  Map of West Virginia highlighting Wetzel County | |
| Towns | ||
| CDPs | ||
| Unincorporated communities |
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| Ghost towns | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
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