1824 United States presidential election in Maine

The 1824 United States presidential election in Maine took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Maine

October 26 – December 2, 1824

Nominee John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Home state Massachusetts Georgia Running mate John C. Calhoun Nathaniel Macon Electoral vote 9 0 Popular vote 10,289 2,336 Percentage 81.50% 18.50%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Maine voted for John Quincy Adams over William H. Crawford, Henry Clay, and Andrew Jackson. Adams won Maine by a margin of 63.0%.

Results

1824 United States presidential election in Maine[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	John Quincy Adams	10,289	81.50%	9
	Democratic-Republican	William H. Crawford	2,336	18.50%	0
Totals			12,625	100.0%	9

See also

• United States presidential elections in Maine

References

1. "1824 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 27 February 2013.