1824 United States presidential election in Connecticut

The 1824 United States presidential election in Connecticut took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1824 United States presidential election in Connecticut

October 26 – December 2, 1824

Nominee John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Home state Massachusetts Georgia Running mate John C. Calhoun Nathaniel Macon Electoral vote 8 0 Popular vote 7,494 1,965 Percentage 70.39% 18.46%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Connecticut voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won Connecticut by a margin of 51.93%.

Results

1824 United States presidential election in Connecticut[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	John Quincy Adams	7,494	70.39%	8
	Democratic-Republican	William H. Crawford	1,965	18.46%	0
	N/A	Other	1,188	11.16%	0
Totals			10,647	100.0%	8

See also

• United States presidential elections in Connecticut

References

1. "1824 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 27 February 2013.