1892 United States presidential election in Wisconsin

The 1892 United States presidential election in Wisconsin was held on November 8, 1892 as part of the 1892 United States presidential election. Wisconsin voters chose twelve electors to the Electoral College, who voted for president and vice president.

1892 United States presidential election in Wisconsin

November 8, 1892

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Adlai Stevenson I Whitelaw Reid Electoral vote 12 0 Popular vote 177,325 171,101 Percentage 47.72% 46.05%

County Results Cleveland   40-50%   50-60%   60-70%   70-80% Harrison   40-50%   50-60%   60-70%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

Democratic Party candidate Grover Cleveland won Wisconsin with 47.72 percent of the popular vote, winning the state's twelve electoral votes.[1] As a result of his win, Cleveland became the first Democratic presidential candidate since Franklin Pierce in 1852 to win Wisconsin. No Democrat would win Wisconsin again until Woodrow Wilson in 1912.

Results

1892 United States presidential election in Wisconsin
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Grover Cleveland	177,325	47.72%	12
	Republican	Benjamin Harrison (incumbent)	171,101	46.05%	0
	Prohibition	John Bidwell	13,136	3.54%	0
	People's	James Weaver	10,019	2.7%	0
Totals			371,581	100.0%	12

References

1. "1892 Presidential General Election Results – Wisconsin". Retrieved August 18, 2016.