1812 United States presidential election in Vermont

The 1812 United States presidential election in Vermont took place between October 30 and December 2, 1812, as part of the 1812 United States presidential election. The state legislature chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1812 United States presidential election
1812 United States presidential election in Vermont
October 30 – December 2, 1812
 
Nominee James Madison
Party Democratic-Republican
Home state Virginia
Running mate Elbridge Gerry
Electoral vote 8
Percentage 100%
President before election

James Madison
Democratic-Republican

 Elected President

James Madison
Democratic-Republican

Elections in Vermont
Federal offices
Presidential elections
U.S. Senate elections
Class One
Class Three
U.S. House elections
Special elections
State offices
General elections
Gubernatorial elections
Legislative elections
Senate
House of Representatives
Municipal offices
Mayoral elections
City of Burlington
City of Rutland

During this election, Vermont cast its eight electoral votes to Democratic Republican candidate and incumbent President James Madison. For the second time in the state's history, Vermont became the only state in New England to vote for Madison, as the other 4 New England states cast their electoral votes for Federalist supported candidate DeWitt Clinton.

See also

References
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