1856 United States presidential election in Vermont
The 1856 United States presidential election in Vermont took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Vermont |
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Vermont voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 57.12%.
With 77.96% of the popular vote, Vermont would be his strongest victory in the Union in terms of percentage in the popular vote.[1]
Frémont's victory also started the long streak of Republican presidential candidate victories within the Green Mountain State, which wouldn't be broken until 108 years later in 1964.
Results
1856 United States presidential election in Vermont[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | John C. Frémont of California | William L. Dayton of New Jersey | 39,561 | 77.96% | 5 | 100.00% | ||
Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 10,577 | 20.84% | 0 | 0.00% | ||
Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 545 | 1.07% | 0 | 0.00% | ||
N/A | Others | Others | 65 | 0.13% | 0 | 0.00% | ||
Total | 47,922 | 100.00% | 5 | 100.00% |
References
- "1856 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1856 Presidential General Election Results - Vermont".