1828 United States presidential election in Georgia

In the 1828 United States presidential election, Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.

1828 United States presidential election in Georgia

October 31 – December 2, 1828

Nominee Andrew Jackson John Quincy Adams Party Democratic National Republican Home state Tennessee Massachusetts Running mate John C. Calhoun Richard Rush Electoral vote 9 0 Popular vote 19,362 642 Percentage 96.79% 3.21%

Seven Georgian electors voted for William Smith for vice president, rather than Jackson's official running mate, John C. Calhoun.[1]

Results

United States presidential election in Georgia, 1828[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson	19,362	96.79%	9
	National Republican	John Quincy Adams	642	3.21%	0
Totals			20,004	100.0%	9

References

1. "Electoral Votes for President and Vice President, 1821-1837 – 1828 Election for the Eleventh Term". National Archives and Records Administration. Retrieved 6 September 2018.
2. "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 28 February 2013.