1828 United States presidential election in Massachusetts

The 1828 United States presidential election in Massachusetts took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Massachusetts

October 31 – December 2, 1828
Turnout	25.7%[1] 3.3 pp
Nominee John Quincy Adams Andrew Jackson Party National Republican Democratic Home state Massachusetts Tennessee Running mate Richard Rush John C. Calhoun Electoral vote 15 0 Popular vote 29,836 6,012 Percentage 76.36% 15.39%

Massachusetts voted for the National Republican candidate, incumbent president John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Massachusetts by a margin of 60.97%.

With 76.36% of the popular vote, Adams' home state would prove to be his second strongest victory in the 1828 election after neighboring Rhode Island.[2]

Results

1828 United States presidential election in Massachusetts[3]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	John Quincy Adams	29,836	76.36%	15
	Democratic	Andrew Jackson	6,012	15.39%	0
	N/A	Other	3,226	8.26%	0
Totals			39,074	100.0%	15

See also

• United States presidential elections in Massachusetts

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
3. "1828 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 28 February 2013.