1848 United States presidential election in Iowa

The 1848 United States presidential election in Iowa took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1848 United States presidential election in Iowa

November 7, 1848

Nominee Lewis Cass Zachary Taylor Party Democratic Whig Home state Michigan Louisiana Running mate William O. Butler Millard Fillmore Electoral vote 4 0 Popular vote 11,238 9,930 Percentage 50.46% 44.59%

President before election James K. Polk Democratic Elected President Zachary Taylor Whig

Iowa voted for the Democratic candidate Lewis Cass in the state's first presidential election, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Iowa by a margin of 5.87%.

Results

1848 United States presidential election in Iowa[1][2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Lewis Cass of Michigan	William O. Butler of Kentucky	11,238	50.46%	4	100.00%
	Whig	Zachary Taylor of Louisiana	Millard Fillmore of New York	9,930	44.59%	0	0.00%
	Free Soil	Martin Van Buren of New York	Charles F. Adams, Sr. of Massachusetts	1,103	4.95%	0	0.00%
Total				22,271	100.00%	4	100.00%

References

1. "1848 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 27 December 2013.
2. "1848 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 27 December 2013.