1944 Iowa gubernatorial election

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

1944 Iowa gubernatorial election

November 7, 1944

Nominee Robert D. Blue Richard F. Mitchell Party Republican Democratic Popular vote 561,827 437,684 Percentage 56.01% 43.63%

Governor before election Bourke B. Hickenlooper Republican Elected Governor Robert D. Blue Republican

Primary elections

Primary elections were held on June 5, 1944.[1]

Candidates

• Richard F. Mitchell, former Associate Justice of the Iowa Supreme Court

Results

Democratic primary results[1]

Party		Candidate	Votes	%
	Democratic	Richard F. Mitchell	38,086	100.00
Total votes			38,086	100.00

Candidates

• Robert D. Blue, incumbent Lieutenant Governor
• Henry W. Burma, Speaker of the Iowa House of Representatives
• Milton W. Strickler, former State Representative

Results

Republican primary results[1]

Party		Candidate	Votes	%
	Republican	Robert D. Blue	102,246
	Republican	Henry W. Burma	63,011
	Republican	Milton W. Strickler	9,859
Total votes

General election

Candidates

Major party candidates

• Robert D. Blue, Republican
• Richard F. Mitchell, Democratic

Other candidates

• Glen Williamson, Prohibition
• Hugo Bockewitz, Socialist

Results

1944 Iowa gubernatorial election[2]

Party		Candidate	Votes	%	±%
	Republican	Robert D. Blue	561,827	56.01%
	Democratic	Richard F. Mitchell	437,684	43.63%
	Prohibition	Glen Williamson	2,815	0.28%
	Socialist	Hugo Bockewitz	832	0.08%
Majority			124,143
Turnout
	Republican hold		Swing

References

1. "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.
2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.