1868 United States presidential election in Iowa

The 1868 United States presidential election in Iowa took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1868 United States presidential election
1868 United States presidential election in Iowa
November 3, 1868
 
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Illinois New York
Running mate Schuyler Colfax Francis Preston Blair, Jr.
Electoral vote 8 0
Popular vote 120,399 74,040
Percentage 61.92% 38.08%
President before election

Andrew Johnson
Democratic

 Elected President

Ulysses S. Grant
Republican

Elections in Iowa
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Iowa voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 23.84%.

Results
1868 United States presidential election in Iowa[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 120,399 61.92% 8 100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 74,040 38.08% 0 0.00%
Total 194,439 100.00% 8 100.00%


References
  1. "1868 Presidential General Election Results - Iowa".


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