1940 United States Senate election in Indiana

The 1940 United States Senate election in Indiana took place on November 5, 1940. Incumbent Democratic U.S. Senator Sherman Minton ran for re-election to a second term, but lost narrowly to Republican Raymond E. Willis.

1940 United States Senate election in Indiana
November 5, 1940
 
Nominee Raymond E. Willis Sherman Minton
Party Republican Democratic
Popular vote 888,070 864,803
Percentage 50.45% 49.13%
U.S. senator before election

Sherman Minton
Democratic

 Elected U.S. Senator

Raymond E. Willis
Republican

Elections in Indiana
Federal government
U.S. President
U.S. Senate
U.S. House of Representatives
State government
State elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Evansville
Mayoral Elections
Fort Wayne
Mayoral Elections
Gary
Mayoral Elections
Indianapolis
Mayoral Elections
Before Unigov
Unigov-era
City-County Council Elections
South Bend
Mayoral Elections

General election

Candidates
  • John H. Kingsbury (Socialist)
  • Sherman Minton, incumbent Senator since 1935 (Democratic)
  • Carl W. Thompson (Prohibition)
  • Raymond E. Willis, former State Representative from Angola and nominee for Senate in 1938 (Republican)

Results
1940 U.S. Senate election in Indiana[1][2]
Party Candidate Votes % ±%
Republican Raymond E. Willis 888,070 50.45% 2.97
Democratic Sherman Minton (incumbent) 864,803 49.13% 2.33
Prohibition Carl W. Thompson 5,621 0.32% 0.02
Socialist John H. Kingsbury 1,751 0.10% 0.54
Total votes 1,760,245 100.00%
Republican gain from Democratic

See also

References
  1. Clerk of the U.S. House of Representatives (1941). "Statistics of the Presidential and Congressional Election of November 5, 1940" (PDF). U.S. Government Printing Office.
  2. "Our Campaigns – IN US Senate Race – Nov 05, 1940". www.ourcampaigns.com.
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