1856 United States presidential election in Indiana

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Indiana

November 4, 1856

Nominee James Buchanan John C. Frémont Millard Fillmore Party Democratic Republican Know Nothing Home state Pennsylvania California New York Running mate John C. Breckinridge William L. Dayton Andrew Jackson Donelson Electoral vote 13 0 0 Popular vote 118,670 94,375 22,386 Percentage 50.41% 40.09% 9.51%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32%.

Results

1856 United States presidential election in Indiana[1][2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James Buchanan of Pennsylvania	John C. Breckinridge of Kentucky	118,670	50.41%	13	100.00%
	Republican	John C. Frémont of California	William L. Dayton of New Jersey	94,375	40.09%	0	0.00%
	Know Nothing	Millard Fillmore of New York	Andrew Jackson Donelson of Tennessee	22,386	9.51%	0	0.00%
Total				235,431	100.00%	13	100.00%

See also

• United States presidential elections in Indiana

References

1. "1856 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 3 December 2017.
2. "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.