1812 United States House of Representatives election in Delaware
Delaware gained a seat after the 1810 Census, and chose to elect both seats on a general ticket. The ten years between 1813 and 1823 were the only time when Delaware was represented by more than one Representative, and is one of only three states (the other two being Alaska and Wyoming) that have never been divided into districts.
Elections in Delaware |
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Delaware elected its members October 6, 1812.
District | Incumbent | This race | |||
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Representative | Party | First elected | Results | Candidates | |
Delaware at-large 2 seats on a general ticket |
Henry M. Ridgely | Federalist | 1810 | Incumbent re-elected. | √ Henry M. Ridgely (Federalist) 28.3% √ Thomas Cooper (Federalist) 28.2% David Hall (Democratic-Republican) 21.8% Richard Dale (Democratic-Republican) 21.7% |
None (Seat created) | New seat. New member elected. Federalist gain. |
See also
- United States House of Representatives elections, 1812 and 1813
- List of United States Representatives from Delaware
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