1900 United States presidential election in Delaware

The 1900 United States presidential election in Delaware took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

1900 United States presidential election in Delaware

November 6, 1900

Nominee William McKinley William J. Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Theodore Roosevelt Adlai Stevenson I Electoral vote 3 0 Popular vote 22,535 18,852 Percentage 53.67% 44.90%

County Results McKinley   40-50%   50-60%

President before election William McKinley Republican Elected President William McKinley Republican

Delaware was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.

Results

1900 United States presidential election in Delaware[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	William McKinley	22,535	53.67%	3
	Democratic	William Jennings Bryan	18,852	44.90%	0
	Prohibition	John Woolley	546	1.30%	0
	Social Democratic	Eugene Debs	56	0.13%	0
Totals			41,989	100.00%	3
Voter turnout					—

See also

• United States presidential elections in Delaware

References

1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes