1852 United States presidential election in Delaware

The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Delaware

November 2, 1852

Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William A. Graham Electoral vote 3 0 Popular vote 6,318 6,293 Percentage 49.85% 49.66%

President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Delaware by a very narrow margin of 0.19%.

Results

1852 United States presidential election in Delaware[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William R. King of Alabama	6,318	49.85%	3	100.00%
	Whig	Winfield Scott of New Jersey	William Alexander Graham of North Carolina	6,293	49.66%	0	0.00%
	Free Soil	John P. Hale of New Hampshire	George Washington Julian of Indiana	62	0.49%	0	0.00%
Total				12,673	100.00%	3	100.00%

1852 United States presidential election in Delaware[2]

County	Franklin Pierce Democratic		Winfield Scott Whig		John Hale Free Soil		Margin		Total votes cast
	#	%	#	%	#	%	#	%
Kent	1,422	47.20%	1,591	52.80%	0	0.00%	-169	-5.61%	3,013
New Castle	3,038	51.77%	2,768	47.17%	62	1.06%	270	4.60%	5,868
Sussex	1,858	49.00%	1,934	51.00%	0	0.00%	-76	-2.00%	3,792
Total:	6,318	49.85%	6,293	49.66%	62	0.49%	25	0.20%	12,673

See also

• United States presidential elections in Delaware

References

1. "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 17 March 2015.
2. Burnham, Walter Dean (1955). Presidential ballots, 1836-1892. Internet Archive. Baltimore, Johns Hopkins Press. p. 320.