1888 United States presidential election in Delaware
The 1888 United States presidential election in Delaware took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Delaware |
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Delaware voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 11.64%.
Results
1888 United States presidential election in Delaware[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Grover Cleveland of New York | Allen Granberry Thurman of Ohio | 16,414 | 55.15% | 3 | 100.00% | ||
Republican | Benjamin Harrison of Indiana | Levi Parsons Morton of New York | 12,950 | 43.51% | 0 | 0.00% | ||
Prohibition | Clinton Bowen Fisk of New Jersey | John Anderson Brooks of Missouri | 399 | 1.34% | 0 | 0.00% | ||
N/A | Others | Others | 1 | <0.01% | 0 | 0.00% | ||
Total | 29,764 | 100.00% | 3 | 100.00% |
Notes
References
- "1888 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.
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