1836 United States presidential election in Mississippi

The 1836 United States presidential election in Mississippi took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

November 3 – December 7, 1836

U.S. President
1820 1824 1828 1832 1836 1840 1844 1848 1852 1856 1860 1872 1876 1880 1884 1888 1892 1896 1900 1904 1908 1912 1916 1920 1924 1928 1932 1936 1940 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 Dem Rep 2012 2016 Dem Rep 2020 Dem
U.S. Senate
1817 1820 1820 sp. 1823 1823 1826 sp. 1828 1830 sp. 1833 sp. 1835 1838 1839 sp. 1841 1844 1846 sp. 1848 sp. 1850 1852 sp. 1852 sp. 1854 sp. 1859 1870 1874 1874 sp. 1876 1880 1883 1886 1886 sp. 1889 1892 1894 sp. 1899 1900 1900 sp. 1904 1906 1908 1910 sp. 1912 1916 1918 1922 1924 1928 1930 1934 1936 1940 1941 sp. 1942 1946 1947 sp. 1948 1952 1954 1958 1960 1964 1966 1970 1972 1976 1978 1982 1984 1988 1990 1994 1996 2000 2002 2006 2008 2008 sp. 2012 2014 2018 2018 sp. 2020
U.S. House
1801 1802 (Terr sp) 1806 1817 1819 1820 1822 1824 1826 At-large sp 1828 At-large sp 1830 1832 1835 1837 1839 1841 1843 1845 1847 1849 1851 1853 1855 1857 1858 5th sp 1859 1865 1868 1869 1872 1874 1876 1878 1880 1882 1884 1886 1888 1890 1892 1894 1896 1898 1900 1902 1904 1906 1908 1910 1912 1914 1916 1920 1924 1928 1932 1934 1940 1942 1946 1950 1956 1962 1968 3rd sp 1972 1980 1981 4th sp 1982 1984 1986 1988 1989 5th sp 1990 1992 1994 1996 1998 2006 2008 1st sp 2010 2012 2014 2015 1st sp 2016 2018 2020

Mississippi voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Mississippi by a margin of 2.56%.

Results

United States presidential election in Mississippi, 1836[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	10,297	51.28%	4
	Whig	Hugh White	9,782	48.72%	0
Totals			20,079	100.0%	4

State and district results of the 1836 United States presidential election
Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

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