1836 United States presidential election in Maryland

The 1836 United States presidential election in Maryland took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

November 3 – December 7, 1836


Nominee	William Henry Harrison	Martin Van Buren
Party	Whig	Democratic
Home state	Ohio	New York
Running mate	Francis Granger	Richard Johnson
Electoral vote	10	0
Popular vote	25,852	22,267
Percentage	53.73%	46.27%

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Question P

Maryland voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Maryland by a margin of 7.46%.

Results

1836 United States presidential election in Maryland[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	25,852	53.73%	10
	Democratic	Martin Van Buren	22,267	46.27%	0
Totals			48,119	100.0%	10

References

"1836 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 4 August 2012.

State and district results of the 1836 United States presidential election
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1836 United States presidential election in Maryland

Results

See also

References