1836 United States presidential election in New Hampshire

The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1836 United States presidential election
1836 United States presidential election in New Hampshire
November 3 - December 7, 1836
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Mentor Johnson Francis Granger
Electoral vote 7 0
Popular vote 18,697 6,228
Percentage 75.01% 24.99%
President before election

Andrew Jackson
Democratic

 Elected President

Martin Van Buren
Democratic

Elections in New Hampshire
Federal government
Presidential elections
United States Senate elections
United States House elections
State government
Gubernatorial elections
Executive Council elections
General Court elections
Senate elections
House elections
Manchester
Mayoral elections

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%.

Results
1836 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 18,697 75.01% 7 100.00%
Whig William Henry Harrison of Ohio Francis Granger of New York 6,228 24.99% 0 0.00%
Total 24,925 100.00% 7 100.00%

See also

References
  1. "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.


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