1836 United States presidential election in Kentucky

The 1836 United States presidential election in Kentucky took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

November 3 – December 7, 1836


Nominee	William Henry Harrison	Martin Van Buren
Party	Whig	Democratic
Home state	Ohio	New York
Running mate	Francis Granger	Richard Johnson
Electoral vote	15	0
Popular vote	36,861	33,229
Percentage	52.59%	47.41%

Federal government

Presidential elections
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House of Representatives elections
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State government

Gubernatorial elections
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Secretary of State elections
2011
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State Treasurer elections
2011
Auditor of Public Accounts elections
2011
State elections
2007 2011 2015 2018 2019

Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results

United States presidential election in Kentucky, 1836[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	36,861	52.59%	15
	Democratic	Martin Van Buren	33,229	47.41%	0
Totals			70,090	100.0%	15

References

"1836 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 4 August 2012.

State and district results of the 1836 United States presidential election
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