1840 United States presidential election in North Carolina
The 1840 United States presidential election in North Carolina took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in North Carolina |
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North Carolina voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won North Carolina by a margin of 15.36%.
With 57.68% of the popular vote, North Carolina would prove to be Harrison's fifth strongest state after Kentucky, Vermont, Rhode Island and Louisiana.[1]
Results
United States presidential election in North Carolina, 1840[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 46,567 | 57.68% | 15 | 100.00% | ||
Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 34,168 | 42.32% | 0 | 0.00% | ||
Total | 80,735 | 100.00% | 15 | 100.00% |
References
- "1840 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1840 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved 23 December 2013.
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