1864 United States presidential election in Pennsylvania

The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1864 United States presidential election
1864 United States presidential election in Pennsylvania
November 8, 1864
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 26 0
Popular vote 296,391 276,316
Percentage 51.75% 48.25%
President before election

Abraham Lincoln
Republican

 Elected President

Abraham Lincoln
National Union

Elections in Pennsylvania
Federal government
U.S. President
U.S. Senate
Class One
Class Three
U.S. House of Representatives
State government
Governor
Lieutenant Governor
Attorney General
Auditor General
State Treasurer
State Senate
State House Elections
Elections by year
State elections
Philadelphia
Mayoral elections
City Council elections
Other municipal elections
Pittsburgh
Mayors
Lancaster
Mayors
Allentown
Mayors
Harrisburg
Mayors

Pennsylvania voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won Pennsylvania by a narrow margin of 3.5%.

Results
1864 United States presidential election in Pennsylvania[1]
Party Candidate Votes Percentage Electoral votes
National Union Abraham Lincoln 296,391 51.75% 26
Democratic George B. McClellan 276,316 48.25% 0
Totals 572,707 100.0% 26

See also

References
  1. "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.


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