1880 Rhode Island gubernatorial election

The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.

1880 Rhode Island gubernatorial election
April 7, 1880
 
Nominee Alfred H. Littlefield Horace A. Kimball Albert C. Howard
Party Republican Democratic Independent
Popular vote 10,224 7,440 5,047
Percentage 44.82% 32.62% 22.13%
Governor before election

Charles C. Van Zandt
Republican

 Elected Governor

Alfred H. Littlefield
Republican

Elections in Rhode Island
Federal government
U.S. President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Providence
Mayoral elections

General election

Candidates

Major party candidates

  • Alfred H. Littlefield, Republican
  • Horace A. Kimball, Democratic

Other candidates

  • Albert C. Howard, Independent

Results
1880 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Alfred H. Littlefield 10,224 44.82%
Democratic Horace A. Kimball 7,440 32.62%
Independent Albert C. Howard 5,047 22.13%
Majority 2,784
Turnout
Republican hold Swing

References
  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 27, 2020.
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