1902 Rhode Island gubernatorial election

The 1902 Rhode Island gubernatorial election was held on November 4, 1902. Democratic nominee Lucius F. C. Garvin defeated incumbent Republican Charles D. Kimball with 53.99% of the vote.

1902 Rhode Island gubernatorial election
November 4, 1902
 
Nominee Lucius F. C. Garvin Charles D. Kimball
Party Democratic Republican
Popular vote 32,279 24,541
Percentage 53.99% 41.04%
Governor before election

Charles D. Kimball
Republican

 Elected Governor

Lucius F. C. Garvin
Democratic

Elections in Rhode Island
Federal government
U.S. President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Providence
Mayoral elections

General election

Candidates

Major party candidates

  • Lucius F. C. Garvin, Democratic
  • Charles D. Kimball, Republican

Other candidates

  • William E. Brightman, Prohibition
  • Peter McDermott, Socialist Labor

Results
1902 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Democratic Lucius F. C. Garvin 32,279 53.99%
Republican Charles D. Kimball 24,541 41.04%
Prohibition William E. Brightman 1,689 2.83%
Socialist Labor Peter McDermott 1,283 2.15%
Majority 7,738
Turnout
Democratic gain from Republican Swing

References
  1. Moore, John Leo (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 13, 2020.
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