1930 Rhode Island gubernatorial election

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

1930 Rhode Island gubernatorial election
November 4, 1930
 
Nominee Norman S. Case Theodore F. Green
Party Republican Democratic
Popular vote 112,070 108,558
Percentage 50.53% 48.95%
Governor before election

Norman S. Case
Republican

 Elected Governor

Norman S. Case
Republican

Elections in Rhode Island
Federal government
U.S. President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Providence
Mayoral elections

General election

Candidates

Major party candidates

  • Norman S. Case, Republican
  • Theodore F. Green, Democratic

Other candidates

  • Charles H. Dana, Socialist

Results
1930 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Norman S. Case 112,070 50.53%
Democratic Theodore F. Green 108,558 48.95%
Socialist Charles H. Dana 1,168 0.53%
Majority 3,512
Turnout
Republican hold Swing

References
  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 7, 2020.
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