1976 United States presidential election in Rhode Island

The 1976 United States presidential election in Rhode Island took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

1976 United States presidential election in Rhode Island

November 2, 1976
Turnout	76.4%[1]
Nominee Jimmy Carter Gerald Ford Party Democratic Republican Home state Georgia Michigan Running mate Walter Mondale Bob Dole Electoral vote 4 0 Popular vote 227,636 181,249 Percentage 55.4% 44.1%
County Results Carter   40-50%   50-60%
President before election Gerald Ford Republican Elected President Jimmy Carter Democratic

Rhode Island was won by Jimmy Carter (D–Georgia), with 55.36% of the popular vote. Carter defeated incumbent President Gerald Ford (R–Michigan), who finished with 44.08% of the popular vote. No third-party candidate received any votes.

Jimmy Carter went on to become the 39th president of the United States.[2]

Results

1976 United States presidential election in Rhode Island

Party		Candidate	Votes	%
	Democratic	Jimmy Carter	227,636	55.36%
	Republican	Gerald Ford (inc.)	181,249	44.08%
	Write-In		2,285	0.56%
Total votes			411,170	100%

By county

County	Carter%	Carter#	Ford%	Ford#	Others%	Others#
Providence	58%	144,805	41.6%	103,976	0.4%	1,036
Newport	53.7%	17,768	45.8%	15,155	0.6%	184
Bristol	52.4%	11,228	47.3%	10,131	0.3%	66
Kent	51.1%	35,855	48.6%	34,131	0.3%	227
Washington	49.9%	17,980	49.6%	17,856	0.5%	186

See also

• United States presidential elections in Rhode Island

References

1. This figure is calculated by dividing the total number of votes cast in 1976 (416,583) by an estimate of the number of registered voters in Rhode Island in 1976 (544,992). See "General Election November 2, 1976". Rhode Island Board of Elections. Retrieved February 6, 2018.
2. http://uselectionatlas.org/RESULTS/index.html