1904 United States presidential election in Minnesota
The 1904 United States presidential election in Minnesota took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Minnesota voters chose eleven electors to the Electoral College, which selected the president and vice president.
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Roosevelt 50-60% 60-70% 70-80% 80-90% 90-100%
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Elections in Minnesota |
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Minnesota was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. The ticket won the state by a margin of 55.14%.
With 73.98% of the popular vote, Minnesota would be Roosevelt's third strongest victory in terms of percentage in the popular vote after Vermont and North Dakota.[1]
Results
1904 United States presidential election in Minnesota[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Theodore Roosevelt | 216,651 | 73.98% | 11 | |
Democratic | Alton B. Parker | 55,187 | 18.84% | 0 | |
Social Democratic | Eugene Debs | 11,692 | 3.99% | 0 | |
Prohibition | Silas C. Swallow | 6,253 | 2.14% | 0 | |
Populist | Thomas E. Watson | 2,103 | 0.72% | 0 | |
Socialist Labor | Charles H. Corregan | 974 | 0.33% | 0 | |
Totals | 292,860 | 100.00% | 11 | ||
Voter turnout | — |
References
- "1904 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota
Notes
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