1900 United States presidential election in Minnesota

The 1900 United States presidential election in Minnesota took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

1900 United States presidential election in Minnesota

November 6, 1900

Nominee William McKinley William J. Bryan Party Republican Democratic Home state Ohio Nebraska Running mate Theodore Roosevelt Adlai Stevenson I Electoral vote 9 0 Popular vote 190,461 112,901 Percentage 60.21% 35.69%

County Results McKinley   40-50%   50-60%   60-70%   70-80%   80-90% Bryan   40-50%   50-60%   60-70%

President before election William McKinley Republican Elected President William McKinley Republican

Minnesota was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. The ticket won the state by a margin of 24.52%.

With 60.21% of the popular vote, Minnesota would be McKinley's fifth strongest victory in terms of percentage in the popular vote after Vermont, North Dakota, Maine and Pennsylvania.[1]

Results

1900 United States presidential election in Minnesota[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	William McKinley	190,461	60.21%	9
	Democratic	William Jennings Bryan	112,901	35.69%	0
	Prohibition	John Woolley	8,555	2.70%	0
	Social Democratic	Eugene Debs	3,065	0.97%	0
	Socialist Labor	Joseph Maloney	1,329	0.42%	0
Totals			316,311	100.00%	9
Voter turnout					—

References

1. "1900 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
2. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Minnesota

Notes