1868 United States presidential election in Massachusetts

The 1868 United States presidential election in Massachusetts took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

1868 United States presidential election in Massachusetts

November 3, 1868
Turnout	66.9[1] 3.1 pp
Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Illinois New York Running mate Schuyler Colfax Francis Preston Blair, Jr. Electoral vote 12 0 Popular vote 136,379 59,103 Percentage 69.76% 30.23%
President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

Massachusetts voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 39.53%.

With 69.76% of the popular vote, Massachusetts would be Grant's second strongest victory in terms of popular vote percentage after neighboring Vermont.[2]

Results

1868 United States presidential election in Massachusetts[3]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	136,379	69.76%	12	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	59,103	30.23%	0	0.00%
	N/A	Others	Others	26	0.01%	0	0.00%
Total				195,508	100.00%	12	100.00%

See also

• United States presidential elections in Massachusetts

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
3. "1868 Presidential General Election Results - Massachusetts".