1856 United States presidential election in Kentucky

The 1856 United States presidential election in Kentucky took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Kentucky

November 4, 1856

Nominee James Buchanan Millard Fillmore Party Democratic Know Nothing Home state Pennsylvania New York Running mate John C. Breckinridge Andrew Jackson Donelson Electoral vote 12 0 Popular vote 74,642 67,416 Percentage 52.54% 47.46%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

Kentucky voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Kentucky by a margin of 5.08%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results

United States presidential election in Kentucky, 1856[1][2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James Buchanan of Pennsylvania	John C. Breckinridge of Kentucky	74,642	52.54%	12	100.00%
	Know Nothing	Millard Fillmore of New York	Andrew Jackson Donelson of Tennessee	67,416	47.46%	0	0.00%
Total				142,058	100.00%	12	100.00%

References

1. "1856 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 3 December 2017.
2. "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.