1860 United States presidential election in Oregon

The 1860 United States presidential election in Oregon took place on November 6, 1860, as part of the 1860 United States presidential election. Oregon voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

1860 United States presidential election in Oregon

November 6, 1860

Nominee Abraham Lincoln John C. Breckinridge Stephen A. Douglas Party Republican Southern Democratic Democratic Home state Illinois Kentucky Illinois Running mate Hannibal Hamlin Joseph Lane Herschel V. Johnson Electoral vote 3 0 0 Popular vote 5,344 5,074 4,131 Percentage 36.20% 34.37% 27.99%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

Oregon voted in its first ever presidential election, having become the 33rd state on February 14, 1859. The state was won by Illinois Representative Abraham Lincoln (R–Kentucky), running with Senator Hannibal Hamlin, with 36.20% of the popular vote, against the 14th Vice President of the United States John C. Breckinridge (SD–Kentucky), running with Senator Joseph Lane, with 34.37% of the popular vote and Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 27.99% of the popular vote.

Results

1860 United States presidential election in Oregon[1]

Party		Candidate	Votes	%
	Republican	Abraham Lincoln	5,344	36.20%
	Southern Democratic	John C. Breckinridge	5,074	34.37%
	Democratic	Stephen A. Douglas	4,131	27.99%
	Constitutional Union	John Bell	212	1.44%
Total votes			14,761	100%

References

1. "1860 Presidential Election Results Oregon".