1860 United States presidential election in New Hampshire

The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.

1860 United States presidential election in New Hampshire

November 2, 1860

Nominee Abraham Lincoln Stephen A. Douglas Party Republican Democratic Home state Illinois Illinois Running mate Hannibal Hamlin Herschel V. Johnson Electoral vote 5 0 Popular vote 37,519 25,887 Percentage 56.90% 39.26%

County Results Lincoln   40-50%   50-60%   60-70%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.61%.

Results

1860 United States presidential election in New Hampshire[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Abraham Lincoln of Illinois	Hannibal Hamlin of Maine	37,519	56.90%	5	100.00%
	Democratic	Stephen A. Douglas of Illinois	Herschel Vespasian Johnson of Georgia	25,887	39.29%	0	0.00%
	Southern Democratic	John C. Breckinridge of Kentucky	Joseph Lane of Oregon	2,125	3.22%	0	0.00%
	Constitutional Union	John Bell of Tennessee	Edward Everett of Massachusetts	412	0.62%	0	0.00%
Total				65,943	100.00%	5	100.00%

See also

• United States presidential elections in New Hampshire

References

1. "1860 Presidential General Election Results - New Hampshire".