1860 United States presidential election in Kentucky

The 1860 United States presidential election in Kentucky took place on November 6, 1860, as part of the 1860 United States presidential election. Kentucky voters chose 12 representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1860 United States presidential election in Kentucky

November 6, 1860

Nominee John Bell John Breckenridge Stephen A. Douglas Party Constitutional Union Southern Democratic Democratic Home state Tennessee Kentucky Illinois Running mate Edward Everett Joseph Lane Herschel V. Johnson Electoral vote 12 0 0 Popular vote 66,058 53,143 25,651 Percentage 45.18% 36.35% 17.54%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

Kentucky was won by the Senator John Bell (CU–Tennessee), running with the Governor of Massachusetts Edward Everett, with 45.18% of the popular vote, against 14th Vice President of the United States John Breckenridge (SD–Kentucky), running with Senator Joseph Lane, with 36.35% of the popular vote and the 15th Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 17.54% of the popular vote.[1]

Despite former representative Abraham Lincoln (R-Illinois) having been born and raised for the first five years of his life in Kentucky, he came in a distant fourth, failing to win 1% of the vote. Even worse, Lincoln failed to win LaRue County, the location of his birth. As of the 2020 presidential election, this is the last election in which Clay County voted for a Democratic candidate.

Results

1860 United States presidential election in Kentucky[1]

Party		Candidate	Votes	%
	Constitutional Union	John Bell	66,058	45.18%
	Southern Democratic	John C. Breckinridge	53,143	36.35%
	Democratic	Stephen A. Douglas	25,651	17.54%
	Republican	Abraham Lincoln	1,364	0.93%
Total votes			146,216	100%

References

1. "1860 Presidential Election Results Kentucky".