1884 United States presidential election in Arkansas

The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose sixteen electors to the Electoral College, which selected the president and vice president. Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.

1884 United States presidential election in Arkansas

November 4, 1884

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 7 0 Popular vote 72,734 51,198 Percentage 57.83% 40.70%

County Results Cleveland   40-50%   50-60%   60-70%   70-80%   80-90%   90-100% Blaine   50-60%   60-70%   70-80%   80-90%   90-100%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Results

1884 United States presidential election in Arkansas[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	72,734	57.83%	7	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	51,198	40.70%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	1,847	1.47%	0	0.00%
Total				125,779	100.00%	7	100.00%

References

1. "1884 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved November 25, 2020.