1868 United States presidential election in Arkansas

The 1868 United States presidential election in Arkansas took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in Arkansas, 1868

November 3, 1868

Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Illinois New York Running mate Schuyler Colfax Francis Preston Blair, Jr. Electoral vote 5 0 Popular vote 22,112 19,078 Percentage 53.68% 46.32%

President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

Arkansas voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 7.36%.

This was the first time since 1860 that a presidential election was held in the state due to secession, the American Civil War, and Reconstruction. This was also the first presidential election in which a Republican won Arkansas, which it would do next election, but would not do so again until over a century later when Richard Nixon carried the state in the 1972 election.

Results

United States presidential election in Arkansas, 1868[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	22,112	53.68%	5	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	19,078	46.32%	0	0.00%
Total				41,190	100.00%	5	100.00%

References

1. "1868 Presidential General Election Results - Arkansas".