1890 United States House of Representatives election in Wyoming

There were two United States House of Representatives elections in Wyoming in 1890, both held on September 11, 1890. Republican lawyer Clarence D. Clark defeated Democratic George T. Beck with 58.22% of the vote and became the first person to represent Wyoming in the House of Representatives.

1890 United States House of Representatives elections in Wyoming
September 11, 1890 (1890-09-11)
 
Nominee Clarence D. Clark George T. Beck
Party Republican Democratic
Popular vote 9,087 6,520
Percentage 58.22% 41.78%
Elected U.S. Representative

Clarence D. Clark
Republican

Elections in Wyoming
Federal government
President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
Secretary of State elections
Senate elections
House of Representatives elections

Results
United States House of Representatives election in Wyoming, 1890[1]
Party Candidate Votes %
Republican Clarence D. Clark 9,087 58.22%
Democratic George T. Beck 6,520 41.78%
Total votes 15,607 100%

References
  1. "United States House of Representatives election in Wyoming, 1890".


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.