1998 United States House of Representatives election in Wyoming
The 1998 United States House of Representatives election in Wyoming were held on November 3, 1998 to determine who will represent the state of Wyoming in the United States House of Representatives. Wyoming has one, at large district in the House, apportioned according to the 1990 United States Census, due to its low population. Representatives are elected for two-year terms.
Elections in Wyoming |
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Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Barbara Cubin (inc.) | 100,687 | 57.79 | |
Democratic | Scott Farris | 67,399 | 38.69 | |
Libertarian | Steve Richardson | 6,133 | 3.52 | |
Total votes | 174,219 | 100.00 | ||
Republican hold | ||||
References
Preceded by 1996 elections |
United States House elections in Wyoming 1998 |
Succeeded by 2000 elections |
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