1988 United States presidential election in the District of Columbia

The 1988 United States presidential election in the District of Columbia took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

1988 United States presidential election in the District of Columbia

November 8, 1988

Nominee Michael Dukakis George H. W. Bush Party Democratic Republican Home state Massachusetts Texas Running mate Lloyd Bentsen Dan Quayle Electoral vote 3 0 Popular vote 159,407 27,590 Percentage 82.65% 14.30%

District Result Dukakis   80-90%

President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

Washington, D.C. was a landslide in favor of the Democratic candidate, Governor Michael Dukakis of Massachusetts. Vice President George H. W. Bush received 14.3% of the vote. This is the most recent election in which the Republican candidate received more than 10% of the vote in Washington, D.C. This is one of the only two areas in the country that went more Republican than that of 1984, the other being Tennessee.

Results

1988 United States presidential election in the District of Columbia[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Michael Dukakis	159,407	82.65%	3
	Republican	George H. W. Bush	27,590	14.30%	0
	New Alliance	Lenora Fulani	2,901	1.50%	0
	Libertarian	Ron Paul	554	0.29%	0

See also

• United States presidential elections in Washington, D.C.

References

1. http://uselectionatlas.org/RESULTS/state.php?year=1988&fips=11&f=0&off=0&elect=0&minper=0