1832 United States presidential election in Kentucky

The 1832 United States presidential election in Kentucky took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1832 United States presidential election in Kentucky

November 2 – December 5, 1832

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 15 0 Popular vote 43,449 36,292 Percentage 54.49% 45.51%

Kentucky voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Kentucky by a margin of 8.98%. Clay's victory came in large part due to the fact that he was a Kentuckian himself and enjoyed significant popularity in the state.

Results

United States presidential election in Kentucky, 1832[1]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	Henry Clay	43,449	54.49%	15
	Democratic	Andrew Jackson	36,292	45.51%	0
Totals			79,741	100.0%	15

References

1. "1832 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 12 April 2013.