1868 United States presidential election in Maryland

The 1868 United States presidential election in Maryland took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1868 United States presidential election in Maryland

November 3, 1868

Nominee Horatio Seymour Ulysses S. Grant Party Democratic Republican Home state New York Illinois Running mate Francis Preston Blair, Jr. Schuyler Colfax Electoral vote 7 0 Popular vote 62,357 30,438 Percentage 67.20% 32.80%

President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

Maryland voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 34.4%.

With 67.2% of the popular vote, Maryland would be Seymour's third strongest victory in terms of percentage in the popular vote after Kentucky and Louisiana.[1]

Results

1868 United States presidential election in Maryland[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Horatio Seymour of New York	Francis Preston Blair, Jr. of Missouri	62,357	67.20%	7	100.00%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	30,438	32.80%	0	0.00%
Total				92,795	100.00%	7	100.00%

See also

• United States presidential elections in Maryland

References

1. "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
2. "1868 Presidential General Election Results - Maryland".